# Alternation without for loop

조회 수: 1(최근 30일)
JamJan 2019년 10월 15일
댓글: J. Alex Lee 2019년 10월 15일
I have 2 vectors that I want to alternate
A = [1 2 3 4 5 6 7 8 9 10]
B = [0.5 0.2 0.4 0.8 0.9]
I would like to have the following output (preferably without for loop)
Output = [1 0.5 2 0.2 3 0.4 4 0.8 5 0.9 6 7 8 9 10]
How to do this?
Thanks!

댓글을 달려면 로그인하십시오.

### 답변(3개)

Stephen23 2019년 10월 15일
편집: Stephen23 2019년 10월 15일
>> N = min(numel(A),numel(B));
>> V = [reshape([A(1:N);B(1:N)],1,[]),A(N+1:end),B(N+1:end)]
V =
1 0.5 2 0.2 3 0.4 4 0.8 5 0.9 6 7 8 9 10
##### 댓글 수: 1표시숨기기 없음
J. Alex Lee 2019년 10월 15일
nice...i like when i didn't see the obvious complete opposite path...and i learned a new thing with the empty argument for reshape

댓글을 달려면 로그인하십시오.

Jos (10584) 2019년 10월 15일
% a sorting trick
A = [1 2 3 4 5 6 7 8 9 10]
B = [0.5 0.2 0.4 0.8 0.9]
C = [A B] ;
[~,ix] = sort([1:numel(A) 1:numel(B)])
C = C(ix)
##### 댓글 수: 0표시숨기기 이전 댓글 수: -1

댓글을 달려면 로그인하십시오.

J. Alex Lee 2019년 10월 15일
Here's a possibility: if A and B were guaranteed to be the same length (your example is not) and row vectors, you could do
N = length(A)
Output = reshape([A(:),B(:)]',2*N,1)
If not same length, you can nan-pad the shorter vector and remove later.

댓글을 달려면 로그인하십시오.

### 범주

Find more on Resizing and Reshaping Matrices in Help Center and File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by