How can I save data from features files into matrix?
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i want to save data from 500 images features files every file contain 6 types of features types such as jcd,tamura,..... .,
the problem is that the data for these 6 features are seperated by comma,i want to make six matrices for these 500 image for type of features ,i atteched this file to help
can any one help
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per isakson
2019년 10월 14일
"the problem is that the data for these 6 features are seperated by comma" Why is that a problem?
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per isakson
2019년 10월 15일
편집: per isakson
2019년 10월 15일
I understand that "data for each feature for 500 images" is in ONE text file with 500 blocks of six rows. The format is illustrated by im1.txt which contains two blocks.
Try this
>> S = cssm('im1.txt')
S =
1×2 struct array with fields:
JCD
Tamura
ColorLayout
EdgeHistogram
AutoColorCorrelogram
PHOG
>> JCD_matrix = cat( 1, S(:).JCD );
>> whos JCD_matrix
Name Size Bytes Class Attributes
JCD_matrix 2x168 2688 double
where (in one m-file)
function im = cssm( ffs )
%%
fid = fopen( ffs, 'rt' );
buf = textscan( fid, '%s', 'Delimiter', '\n' );
fclose( fid );
buf = buf{1};
%%
len = floor( size(buf,1)/6 ); % number of blocks
im(1,len) = struct( 'JCD',[], 'Tamura',[], 'ColorLayout',[] ...
, 'EdgeHistogram',[], 'AutoColorCorrelogram',[], 'PHOG',[] );
%%
for jj = 1 : len
im(jj).JCD = read( buf{(jj-1)*6 + 1 }, 'JCD' , (jj-1)*6+1 );
im(jj).Tamura = read( buf{(jj-1)*6 + 2 }, 'Tamura' , (jj-1)*6+2 );
im(jj).ColorLayout = read( buf{(jj-1)*6 + 3 }, 'ColorLayout' , (jj-1)*6+3 );
im(jj).EdgeHistogram = read( buf{(jj-1)*6 + 4 }, 'EdgeHistogram' , (jj-1)*6+4 );
im(jj).AutoColorCorrelogram = read( buf{(jj-1)*6 + 5 }, 'AutoColorCorrelogram', (jj-1)*6+5 );
im(jj).PHOG = read( buf{(jj-1)*6 + 6 }, 'PHOG' , (jj-1)*6+6 );
end
end
function row = read( chr, name, n )
cac = strsplit( chr, ':' );
assert( strcmp(cac{1},name),'Row, %d, is "%s". Expected is "%s"', n, cac{1}, name )
num = textscan( cac{2}, '%f', 'Delimiter',',' );
row = reshape( num{1}, 1,[] );
end
If execution time is a problem replace
cac = strsplit( chr, ':' );
by
cac = regexp( chr, ':', 'split' );
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per isakson
2019년 10월 16일
I wrote: "I understand that "data for each feature for 500 images" is in ONE text file with 500 blocks of six rows. The format is illustrated by im1.txt which contains two blocks."
Why don't you say that I missinterpreted the question?
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