I've got a matrix of 35040x14 (35040x 15minutes). I now want to to get the maximum value per hour over these 14 colomns. I've made the following for the first hour:
myData = 35040x14
oneHour = myData(1:4,:);
maxValuePerHour = max(oneHour);
oneHour gives me a 4x14 matrix which I then took the maximum per column from resulting in a maxValuePerHour matrix of 1x14, as intended. However, I want to loop this process so I end up with a 8760x14 (35040/4) where in the 8760 rows represent maximum values per hour for the entire data set.
Any help would be appreciated. Thank you.

답변 (1개)

Walter Roberson
Walter Roberson 2019년 10월 9일

0 개 추천

squeeze( min( reshape(myData, 4, [], size(myData,2)), 1) )

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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R2019b

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질문:

2019년 10월 9일

답변:

2019년 10월 9일

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