Finding average step size and slope with ode45

조회 수: 5 (최근 30일)
EB
EB 2019년 10월 9일
댓글: Star Strider 2019년 10월 12일
I want to be able to calculate the average step size and slope for each value in the loop.
I first want to plot the log values of dT and TOL.
I believe my average step size (dT) should be the average of 1/T.
t = [0, 5]; % time span
y0 = 1; % initial condition
dy0 = 2; % initial condition first derivative
dydt = @(t,y) [y(2); ((1 - y(1)^2))*y(2) - y(1)];
for j = 1:10
TOL(j) = 1*exp(-1-j);
options = odeset('AbsTol',TOL(j),'RelTol',TOL(j));
[T{j},Y{j}] = ode45(dydt, t, [y0, dy0], options);
dT = mean(1/length(T)); % average step size
plot(log(dT),log(TOL));
hold on;
grid
j = j+1;
end
hold off;
Errors I'm facing:
  • my plot doesn't show up
  • my slope receives the error 'Undefined function 'log' for input arguments of type 'cell'.'
  • not sure if I am thinking of average step size correctly
Side note: Would I be able to generate multiple slopes using polyfit in one graph?

채택된 답변

Star Strider
Star Strider 2019년 10월 9일
Subscript ‘dT’ as well. The code will be more efficient if you move the plot outside the loop:
t = [0, 5]; % time span
y0 = 1; % initial condition
dy0 = 2; % initial condition first derivative
dydt = @(t,y) [y(2); ((1 - y(1)^2))*y(2) - y(1)];
for j = 1:10
TOL(j) = 1*exp(-1-j);
options = odeset('AbsTol',TOL(j),'RelTol',TOL(j));
[T{j},Y{j}] = ode45(dydt, t, [y0, dy0], options);
dT(j) = mean(1/length(T)); % average step size
end
figure
plot(log(dT),log(TOL));
grid
  댓글 수: 3
EB
EB 2019년 10월 12일
I realized my error.
Thanks again!!
Star Strider
Star Strider 2019년 10월 12일
As always, my pleasure!

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