array exceeds maximum array size preference.

clc; 
clear all; 
close all;
t = [0:10^20];
K = 1.38*10^-23;
Me = 9.11*10^-31;
T = 1.3543*10^3;
V = 100*sqrt(3*K*T*11600/Me);
Ne = 1.42*10^24;
Np = 1.42*10^24;
E = 10^6;
b = (7.56*10^-16)*(6.24*10^18)*((11600)^4)/((100)^3);
F = ((1.166*10^-23)^2);
Y = sqrt(T^2-((Ne*Np*E*V*F*((1.239*10^-4)^2)*t)/(2*b)));
plot(t, Y)

Answer 1

[the cyclist]

In this line of code

t = [0:10^20];

You are trying to create a vector that is length 10^20.

That is ... uh ... big. If I did my quick math right, that's over a billion terabytes to store.

Answer 2

[Walter Roberson]

0:10^20 requests an array counting 0, 1, 2, 3, all the way to 10^20. That would take about 2^69 bytes to represent. However, no x64 architecture can access more than 2^64 bytes in theory, and no publically released x64 chip can access more than 2^48 bytes -- there are no address lines A48 to A63.

If you did manage to hack an x64 system to have 2^69 bytes of memory, then it would take rather a while to create the array. If you used a multi core system that could initialize 10^10 per second then it would take about 316 years.