How to sdcsd ?

c

[Shubham Gupta]

Not entirely sure, but is this what you want ?

V = [0,0,0,0]';
i = 2;    % change i to assign 1 to the corresponding index
V(i) = 1; % generated V = [0; 2; 0; 0]

You said you 1 vector but your shows 4 different vectors with different name, what output do you want exactly?

[H]

Sorry for the confusion. Actually I want to have N number of vectors. And I gave examples of first 4 of those.

v = zeros(N,1);

for i = 1:N
    v(i) = 1
end

When I do the above, I get all ones in one vector. But I want to generate N number of vectors, depending on the i value, the value "1" would take place on that specific cell, other cells would remain zero.

Answer 1

[John D'Errico]

Don't. Instead, use arrays to store them.

n = 4;
V = eye(n);

V
V =
     1     0     0     0
     0     1     0     0
     0     0     1     0
     0     0     0     1

As you can see, the rows of V are exactly as you wish. You can access the i'th such vector using indexing.

V(2,:)
ans =
     0     1     0     0

Answer 2

[Steven Lord]

Rather than making a large number of variables (which will clutter your workspace and be difficult to work with) instead I recommend making one variable and accessing parts of it as needed.

V = eye(4);
for k = 1:size(V, 2)
    x = V(:, k) % Equivalent of Vk
    % Work with x
end

Actually, if you want to iterate over the columns of V, for has an interesting property if you specify the range over which to iterate as a matrix.

V = eye(4);
for vec = V
    disp(vec)
end

vec will take on each of the columns of V in turn.