I tired for displaying Value of f and conclusion but it seem not working. here is my code:
clc
clear all
syms x y
f(x,y)=x^3-3*x*y+y^3;
fx=diff(f,x);
fy=diff(f,y);
fxx=diff(fx,x);
fyy=diff(fy,y);
fxy=diff(fx,y);
D=(fxx*fyy)-(fxy)^2;
eqns=[fx==0,fy==0];
vars=[x y];
[sol_x sol_y]=solve(fx==0,fy==0,'Real',true);
conclusion={};
f_val=[];
for i=1:length(sol_x)
if( subs(D,{x,y},{sol_x(i),sol_y(i)})>0 && subs(fxx,{x,y},{sol_x(i),sol_y(i)})>0 )
conclusion{end+1}='min';
f_val(end+1)=f(sol_x(i),sol_y(i));
elseif(subs(D,{x,y},{sol_x(i),sol_y(i)})>0 && subs(fxx,{x,y},{sol_x(i),sol_y(i)})<0)
conclusion{end+1}='max';
f_val(end+1)=f(sol_x(i),sol_y(i));
elseif(subs(D,{x,y},{sol_x(i),sol_y(i)})<0)
conclusion{end+1}='saddle';
f_val(end+1)=f(sol_x(i),sol_y(i));
else
conclusion{end+1}='undetermine';
f_val(end+1)=f(sol_x(i),sol_y(i));
end
end
conclusion'
f_val'
result=[num2cell(f_val) conclusion']
error:
Error using horzcat Dimensions of matrices being concatenated are not consistent.
Any solution will be aprreciated.
Thanks in advance.th

댓글 수: 4

there is problem in your last statement. It should looks something like this:
result=[num2cell(f_val) conclusion]
Is this what you are expecting?
result=[num2cell(f_val') conclusion']
Works for only function value and conclusion. I can do same thing with fxx and D but how to display critical point along with these? @Ankit
When you use the following, then there is no error-
result=[num2cell(f_val) conclusion]
The answer provider on this Matlab Answer may not be from the same subject, it would be easy to answer, if you can provide us with the expected result?
emonhossain roy
emonhossain roy 2019년 10월 1일
I attached a picture in my question. I want to display my output like it. Have you seen it? @KALYAN ACHARJYA

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