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error in arrays line 7

조회 수: 1 (최근 30일)
Ronald Aono
Ronald Aono 2019년 9월 29일
댓글: Adam Danz 2019년 9월 30일
function V = fuelvol2(h)
global r H L
validInput = true; %to test each value in the vector h is valid
for i = 1:length(h)
Nh = h(i);
if (Nh < 0 && (Nh > h + 2*r))
validInput = false;
break;
end
end
if validInput == true % if it is valid vector the calculate volume using vectorized operations
d = h-H;
V = 2*r*L*H + (r^2 * acos((r-d)/r) - (r-d).*sqrt(2*r.*d -d.^2))*L;
else
disp("one of more values in vector his/are valid ")
end
I keep getting tis error each time i try to run the code
Not enough input arguments.
Error in fuelvol2 (line 7)
for i = 1:length(h)
  댓글 수: 6
Adam Danz
Adam Danz 2019년 9월 29일
Function calls are case sensitive. There is no matlab function named Length() but there is a function with the lower case length(). However, it's recommended to use numel() instead of length().
Ronald Aono
Ronald Aono 2019년 9월 29일
편집: Adam Danz 2019년 9월 29일
Thank you for the length error, i appriciate it . how do i clear this error to, it keeps creeping up
Operands to the || and && operators must be convertible to logical scalar values.
Error in fuelvol1 (line 7)
if (h>=0) && (h <= (H + 2*r))
Error in main_fuelvol12 (line 7)
V = fuelvol1(h);

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답변 (2개)

Adam Danz
Adam Danz 2019년 9월 29일
It's getting hard to follow the discussion because we're jumping around between different similarly named functions. fuelvol1, fuelvol2, main_fuelvol12.
This error appears to be in fuelvol1 but we don't have access to that function. However, I think the error can be fixed by replacing && with &.

Walter Roberson
Walter Roberson 2019년 9월 30일
편집: Walter Roberson 2019년 9월 30일
for i = 1:length(h)
So you are expecting h to be a non-scalar.
if (Nh < 0 && (Nh > h + 2*r))
You add the non-scalar h to something and compare it to the scalar Nh, producing a non-scalar result on the right hand side of the && . However, the && operator can only be used when both sides are scalars.
Changing to & is not the correct solution. The correct solution is to stop using single-letter variable names that differ only in upper versus lower case, because it is too easy to get the wrong variable name. You do not want h there, you want H .
In your other question, H and 2*r were both positive, and Nh > some_positive_value cannot be simultaneously true with Nh < zero.
  댓글 수: 1
Adam Danz
Adam Danz 2019년 9월 30일
Just curious, from where did you get "for i = 1:length(h)"? I see it in fuelvol2() but the error is in fuelvol1() which we don't have access to, unless I'm missing something.

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