Why in the for cycle the values of the first row of the matrix y(i,j) don't exist?

Hi all,

i'm trying to understand why the first row of the matrix "y(i,j) " isn't considered in my expression "FUNCTIONALITY13". If i run the program, "FUNCTIONALITY13" takes only the values of the last row of "y(i,j)", that is "i=2" .

This is my matrix (as you can see in the code): y(i,j)=[3 5 9; 2 4 8]. FUNCTIONALITY13 takes only the values that corrispond to "state_sys(2,j)" and all the values "state_sys(1,j)" are not taken. Someone could tell me why? How can i do so that FUNCTIONALITY13 takes all values of the matrix "y(i,j)"?

TIMEFAILUREPUM5=[4 6 10];


for j=1:length(TIMEFAILUREPUM5)
    for i=1:2 
  y(i,j)=TIMEFAILUREPUM5(1,j)-i;

if t==(TIMEFAILUREPUM5(1,j)) &&(state_sys(y(i,j))==9||...
      state_sys(y(i,j))==10|| state_sys(y(i,j))==11||state_sys(y(i,j))==12)
  
        FUNCTIONALITY13=max(0, FUN13(t-1)-1);
else
       FUNCTIONALITY13=min(1,FUN13(t-1));
end
    end
end

Thanks to who will help me.

Answer 1

[Shubham Gupta]

I think FUNCTIONALITY13 is being updated after each i, so FUNCTIONALITY13 is not storing all the values as matrix.

You might wanna change the "if...else" loop by

if t==(TIMEFAILUREPUM5(1,j)) &&(state_sys(y(i,j))==9||...
      state_sys(y(i,j))==10|| state_sys(y(i,j))==11||state_sys(y(i,j))==12)
  
        FUNCTIONALITY13(i)=max(0, FUN13(t-1)-1);
else
       FUNCTIONALITY13(i)=min(1,FUN13(t-1));
end

I hope it helps !

[AlexDp]

Thanks for your answer, i will get ideas about it!