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A number contain in a series.

Silpa K 님이 질문을 제출함. 19 Sep 2019
최근 활동 Silpa K 님이 댓글을 추가함. 20 Sep 2019
I have a series 's'
s=(1:1,2:end)
I find its subsequences like
a=s(1:30)
b=s(30:60)
c=s(60:90)
d=s(90:120)
e=s(120:150)
f=s(150:180)
j=s(180:210)
h=s(210:250)
and I have a set of points 'k'.
I need to check any of the subsequence contain any points of the K.If it contain I need to add those subsequence into a variable 'A'.How can I do this.Please help me.

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s = (1:1, 2:end)
is not valid matlab syntax. So, the first problem with your question is we don't really not what your series is.

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thoughtGarden 님의 답변 19 Sep 2019
thoughtGarden 님이 편집함. 20 Sep 2019

You haven't provided enough information to be certain of what you want, but makeing some assumptions, this should work.
clear;clc;
% "series" s, which is an array
s = 1:1:250;
% Build "subsequences"
for ii = 1:7
subSequence(ii,:) = s((ii-1)*30 + 1:ii*30);
end
% Build "set of points 'k'"
k = randi(1000,1,10);
% A will contain all subsequences that contain any of the values of k
A = [];
% In each loop, determine if there is any overlap betweent he subsequence
% and the variable k. If there is, add the subsequency to the variable A.
% Otherwise, move on to the next subsequence.
for ii = 1:length(subSequence(:,1))
if(intersect(subSequence(ii,:),k))
A(end+1,:) = subSequence(ii,:);
else
%do nothing...
end
end
% Disp A, which in the case of this script might be empty as k is random
% values...
disp(A)
This builds an array containing all the subsequences that contain any values found in k. If that is what you are looking for, this works.

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표시 이전 댓글 수: 20
I used different k value that contain in the series s,then also getting an error
Conversion to cell from double is not possible.
Error in example (line 10)
subSequence(ii,:) = s((ii-1)*30 + 1:ii*30);
I need to display the subsequence name that contain k.
[~,ii] = min(abs(s(:) - k(:)'));
out = s(unique(ii));
using this I get nearest elements,now also I can't getting the name of the subsequence

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