Divide an array in n different arrays

Hi, given the array

V = [1 1 1 1 1 1 6 6 6 6 6 6 6 6 6 3 3 3 3 3 3 3 5 5 5 5 5 5 5 8 8 8 8 8 8 8 8 8 9 9 9 9 9 9 9 9 9 4 4 4 4 4 4 4 4 4 4 2 2 2 2 2 1 1 1 1 1 6 6 6 6 6 6 6] 

and the matrix

A = [1 3 4
     6 5 2
     0 8 0
     0 9 0]

I want to obtain 5 different arrays

a = [1 1 1 1 1 1 6 6 6 6 6 6 6 6 6];

b = [ 3 3 3 3 3 3 3 5 5 5 5 5 5 5 8 8 8 8 8 8 8 8 8 9 9 9 9 9 9 9 9 9];

c = [4 4 4 4 4 4 4 4 4 4 2 2 2 2 2 ];

d = [1 1 1 1 1 6 6 6 6 6 6 6];

so every time I meet the elements of one of the columns: 1-6 , 3-5-8-9 or 4-2 , I have to collect them and reported in a new array.

N.B zeros are never present in V, but are just inserted in A to create a square matrix

May someone help me with this task?

Answer 1

[Bruno Luong]

V = [1 1 1 1 1 1 6 6 6 6 6 6 6 6 6 3 3 3 3 3 3 3 5 5 5 5 5 5 5 8 8 8 8 8 8 8 8 8 9 9 9 9 9 9 9 9 9 4 4 4 4 4 4 4 4 4 4 2 2 2 2 2 1 1 1 1 1 6 6 6 6 6 6 6]
A = [1 3 4
6 5 2
0 8 0
0 9 0]

[~,c,a] = find(A);
[~,i] = ismember(V,a);
g = c(i);
d = find([true; diff(g); true]);
c = mat2cell(V,1,diff(d));

c{:}