how to make heatmap have a square-shape?
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when I do
a=rand(4);
heatmap(a);
I got the following image:

How can I make the figure to a square-shaped one? I tried to use
axis equal;
but there's an error: Using axis with heatmap is not supported.
It seems that "axis" is not supported in heatmap.
채택된 답변
  Shubh Sahu
    
 2019년 9월 17일
        Hello Kinger,
heatmap does not support axis command directly but by extracting properties of heatmap, square-shaped figure can be made.  
a=rand(4);
k=heatmap(a);
k.positions=[0.1300 0.1100 0.7179 0.179];
While using above code, make sure that Units property is set to normalized.
Regards,
Shubh
추가 답변 (1개)
  Ramy Rabie
 2020년 6월 6일
        x = [zeros(11,1), 6*ones(11,1) , 137*ones(11,1) ,...
    84*ones(11,1) ,9*ones(11,1) ,4*ones(11,1)]
y = [ ones(1,6) ; 4*ones(1,6)  ; 45*ones(1,6) ;...
    25*ones(1,6) ; 2*ones(1,6) ; 2*ones(1,6) ;...
    13*ones(1,6) ; 52*ones(1,6) ; 58*ones(1,6) ;...
    15*ones(1,6) ; 4*ones(1,6)]
% Making Heatmap figure has square tiles
wposX=100; wposY = 100;
heatmapLength = 500;
heatmapWidth = heatmapLength - (size(y,2)/size(y,1))*heatmapLength;
figure('Renderer', 'painters', 'Position', [wposX wposY heatmapWidth heatmapLength])
tempMap = heatmap(x+y);
% Make heatmap fill the figure
tempMap.InnerPosition = [0 0 1 1];
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