Solve systems of linear equations Ax = B for x

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Johan Johan
Johan Johan 2019년 8월 29일
편집: Stephen23 2019년 8월 29일
x = A\B solves the system of linear equations A*x = B. The matrices A and B must have the same number of rows.
But ,what is the operation between the rows?
There is any one can solve this example–manually ?
A =
1 3
4 2
b= [6 ;7];
>> A\b
ans =
0.9000
1.7000
How to find 0.9 and 1.7 exactly?

채택된 답변

Stephen23
Stephen23 2019년 8월 29일
편집: Stephen23 2019년 8월 29일
"But ,what is the operation between the rows?"
Both mldivide and mrdivide can use many different algorithms for solving systems of linear equations, as documented in the mldivide documentation. There is no single "operation" that describes all of those algorithms.
"There is any one can solve this example–manually ?"
This is easy using standard definitions for solving linear equations, e.g. elimination of variables:
System definition:
First solve the first equation for x:
Second, substitute x back into the second equation:
Third, solve that for y:
And finally try them with your example values:
>> A = [1,3;4,2]
A =
1 3
4 2
>> b = [6;7]
b =
6
7
>> A\b
ans =
0.9
1.7
>> y = (A(1,1)*b(2)-A(2,1)*b(1)) ./ (A(1,1)*A(2,2)-A(2,1)*A(1,2))
y =
1.7
>> x = (b(1)-A(1,2)*y) ./ A(1,1)
x =
0.9

추가 답변 (2개)

KALYAN ACHARJYA
KALYAN ACHARJYA 2019년 8월 29일
편집: KALYAN ACHARJYA 2019년 8월 29일
ans =
0.9000
1.7000
How to find 0.9 and 1.7 exactly??
format shortg;
A =[1 3
4 2];
b= [6 ;7];
A\b
Result:
ans =
0.9
1.7

Torsten
Torsten 2019년 8월 29일
https://en.wikipedia.org/wiki/Cramer%27s_rule

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