Calling evalin with three arguments
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Hi,
according to the documentation for the evalin function, two arguments need to be given when calling it: ws, a string indicating the workspace, and expression, which is a character vector or a string scalar
By mistake, instead of writing
evalin('base','var_name') == 1
I wrote
evalin('base','var_name',1)
To my surprise, this call is accepted, although it just executes as if the third parameter doesn't exist. In fact, by passing pretty much anything as a third parameter, the call works just fine as if it had not been passed (or so it looked to me).
So, what is this third parameter?
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채택된 답변
Stephen23
2019년 8월 29일
편집: Stephen23
2019년 8월 29일
The third (as far as I can tell) totally undocumented input argument provides a default value if a specific variable is not found. For example:
function foo()
disp(evalin('base','x','23'))
end
and then
>> clear()
>> foo()
23
>> x = 5;
>> foo()
5
Of course in actual code, it is much better to use efficient methods of passing data between workspaces, rather than slow and obfuscated evalin, in particular passing input/output arguments or using nested functions:
추가 답변 (1개)
Steven Lord
2019년 8월 29일
In (much) older releases of MATLAB the eval and evalin functions were documented with one more input argument than they are documented to accept now. If the main expression to be evaluated threw an error, that last input argument would be evaluated much like you'd evaluated your main expression in the try section and the last input argument in the catch section of a try / catch block.
While that functionality does remain for backwards compatibility, we removed it from the documentation. A quick check of the archived documentation shows that it was documented in release R13SP2 and not documented in release R14, so it was removed from the documentation fifteen years ago.
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