How to add box to an image?

조회 수: 78 (최근 30일)
Salad Box
Salad Box 2019년 8월 28일
댓글: DGM 2022년 7월 16일
Hi
I have two images ('yellow.png' and 'bird.png'). See below.
1-4.png bird1_before.jpg
How can I make a box AROUND the image borders with self-defined box colours, say all four lines with grey colour [0.5 0.5 0.5]?
See below.
1-1.png 1-2.png
Please can you help?
  댓글 수: 7
Adam Danz
Adam Danz 2019년 8월 28일
편집: Adam Danz 2019년 8월 30일
"The images were first generated in Matlab"
Maybe it would be easier if you altered the code that generated the image. Adding the frame is just 1 line of code. But if you have read the images back into matlab, that's going to be more work.
Based on the code and image in your other comment, it appears the image's bottom, left corner is not at (0,0) where your rectangle starts. See answer.
DGM
DGM 2022년 7월 16일
A grayscale border can be added using IPT padarray(). A colored border requires extra steps, though alternative methods exist. See the following reference answer, which shows various possibilities.

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채택된 답변

Image Analyst
Image Analyst 2019년 8월 30일
편집: Image Analyst 2019년 8월 30일
If the bad lines are always the rightmost one and the bottom one, you can simply crop the image to not include those:
rgbImage = rgbImage(1:end-1, 1:end-1, :);
To pad the image with certain color, you can use padarray() on each color channel. There are other ways. Let me know if it's still a problem for you.

추가 답변 (3개)

Adam Danz
Adam Danz 2019년 8월 28일
편집: Adam Danz 2019년 9월 2일
Use the handle output from imshow to get the image's coordinates. The XData and YData properties will provide you with the coordinates of the image. Unless the image coordinates are specified in imshow() inputs, the first pixel is centered at coordinate (1,1) so the rectangle should begin at (0.5, 0.5). To expand the rectangle to the outer edges, you must add 1 to the width and height indicated by ranges of XData and YData.
% When the image is in pixel units
corn_gray = imread('corn.tif',3);
h = imshow(corn_gray);
rh = rectangle('position',[ ...
h.XData(1)-.5,...
h.YData(1)-.5,...
range(h.XData)+1,...
range(h.YData)+1],...
'EdgeColor', 'r','linewidth',2);
When the image is not in pixel units, XData and YData properties of the image object may no longer indicate the pixel centers so you must compute the location of the pixel edges.
% When the image is not in pixel units
corn_gray = imread('corn.tif',3);
h = imshow(corn_gray,'XData',200:400,'YData',110:4000); %(arbitrary xdata,ydata)
axis square
axis on % optional, to see axis scales
pixelRatio = [range(h.XData)/size(corn_gray,2), range(h.YData)/size(corn_gray,1)];
rh = rectangle('position',[ ...
h.XData(1)-pixelRatio(1)/2,...
h.YData(1)-pixelRatio(2)/2,...
range(h.XData)+pixelRatio(1),...
range(h.YData)+pixelRatio(2)],...
'EdgeColor', 'r','linewidth',2);
% Expand the axis limits to show full frame
xlim(xlim()+[-.01,.01]*range(xlim())) % add 1% to the x axis limits
ylim(ylim()+[-.01,.01]*range(ylim())) % add 1% to the y axis limits

Image Analyst
Image Analyst 2019년 8월 31일
Images rows and columns start with 1, not zero. so do this:
rectangle('position', [1, 1, s(2), s(1)], 'edgecolor', [1 0 0])
If some part of the rectangle is still missing (outside the image), try adding or subtracting 0.5 or 1 to the position values until you can see it. Like perhaps
rectangle('position', [1, 1, s(2) - 1, s(1) - 1], 'edgecolor', [1 0 0])
  댓글 수: 5
Adam Danz
Adam Danz 2019년 9월 3일
편집: Adam Danz 2019년 9월 3일
Then you should have accepted Image Analyst's answer rather than your modification of another person's work.
Salad Box
Salad Box 2020년 1월 30일
I have accepted Image Analyst's anwser.

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Salad Box
Salad Box 2019년 9월 3일
clear
close all
clc
RGB = imread('bird1.jpg');
s = size(RGB);
figure
imshow(RGB);
rectangle('position',[1 1 s(2) s(1)], 'edgecolor', [1 0 0])
rectangle('position',[0 0 s(2) s(1)], 'edgecolor', [1 0 0])
3.png
  댓글 수: 1
Adam Danz
Adam Danz 2019년 9월 3일
편집: Adam Danz 2019년 9월 6일
If you zoom into the image at the rectangle corners you'll see that it doesn't frame the pixel edges because you're not offsetting it by the pixel width & height.

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