Hi,
for r=0:n;
y=factorial(n)/((factorial(n-r))*factorial(r))*((p)^(n-r))*(q)^(r);
end
How to store values of y in array?

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KALYAN ACHARJYA
KALYAN ACHARJYA 2019년 8월 18일
편집: KALYAN ACHARJYA 2019년 8월 18일

1 개 추천

i=1;
y=zeros(1,n+1);
for r=0:n;
y(i)=factorial(n)/((factorial(n-r))*factorial(r))*((p)^(n-r))*(q)^(r);
i=i+1;
end
Or if you can afford to change the for loop range
y=zeros(1,n+1);
for r=1:n+1 % Note: I have change the i srarting value
y(n)=factorial(n)/((factorial(n-r))*factorial(r))*((p)^(n-r))*(q)^(r);
end

댓글 수: 5

thank you sir
My pleasure Samadhan!
Why do you need a loop? @Kalyan?
Yes, @Madhan, I didnot think about it, just answer the question how to store the array values, I did small modification on owner code only.
Yes agreed, Without loop is efficient.
How can i store values of y in array without loop?
Because when i take the different values of y out of the loop it takes only final value. but i need all values of y.

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