Printing row index or row of a matrix by searching for a particular value?

I have a matrix:

mat = [ 4 8 5 3;
       31 4 5 3;
        8 3 1 5];

and I want to display the row index or row of the matrix based on a value at the first column.

For example, the first column of the matrix has values 4, 31 and 8. What I'll want to do then is to print the row index or the whole row containing let's say the value 31 at the first column.. Hence the output will be either:

2 %which is the row index containing 31 as the first value

or

31 4 5 3 %the whole row of the matrix

I used the method of ismember():

idx = ismember(A(:,1),31)

But the problem is a logical array is returned, but if the matrix were to be extremely large, i wouldn't want to go through the whole logical array. I plan to use this for checking purposes.

Answer 1

[the cyclist]

rowIndex = find(mat(:,1)==31); % Row index
row = mat(mat(:,1)==31,:); % Row

Note that one doesn't need the find command to get the row, because logical indexing will be used.

You could also have gotten it using ismember, as you tried, but swap the arguments:

[~,rowIndex] = ismember(31,mat(:,1));

[Stewart Tan]

@the cyclist thank you! just what i needed. cheers!