Need help to put condition in my optimization function

조회 수: 2 (최근 30일)
Shailee Yagnik
Shailee Yagnik 2019년 8월 16일
댓글: Torsten 2019년 8월 26일
Here is my code:
function T0=tw0Solve(t1,s1,s2,rho,P)
T0= fsolve(@(tw0) (exp(-s2.^2./2).*exp(tw0.*s2).*(1-qfunc((t1-s1-rho.*tw0+rho.*s2)./sqrt(1-rho.^2)))./(1-qfunc((t1-rho.*tw0)./sqrt(1-rho.^2))))-P,rand);
end
Where for a given t1 we are trying to find tw0 that minimizes the function T0. But for some initial value the qfunc((t1-s1-rho.*tw0+rho.*s2)./sqrt(1-rho.^2)) becomes =1 which starts to provide error in fsolve as i start to get 0/0 form. How can I put a condition in this that helps me do something like this while it searches for tw0 and encounters a 0/0 form .
if qfunc(t1,tw0) < -3
T0=()
else
T0=()
end

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Torsten
Torsten 2019년 8월 19일
T0= fsolve(@(tw0) (exp(-s2.^2./2).*exp(tw0.*s2).*(1-qfunc((t1-s1-rho.*tw0+rho.*s2)./sqrt(1-rho.^2))))-P*(1-qfunc((t1-rho.*tw0)./sqrt(1-rho.^2))),rand);
  댓글 수: 6
Shailee Yagnik
Shailee Yagnik 2019년 8월 23일
No, it still gives errors for some initial value of two when the initial conditions(s1,s2,rho) changes. Is there a way to put restrictions on two while fsolve function searches for two?
Torsten
Torsten 2019년 8월 26일
Plotting the function which produces problems in the relevant range for "two" might help to get a reasonable initial guess and to identify the cause of errors:
two = linspace(a,b,n);
ftwo = (exp(-s2.^2./2).*exp(tw0.*s2).*(1-qfunc((t1-s1-rho.*tw0+rho.*s2)./sqrt(1-rho.^2))))-P*(1-qfunc((t1-rho.*tw0)./sqrt(1-rho.^2)));
plot (two,ftwo)

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