Interpolating linearly between many values in a vector

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Mitch Hezel
Mitch Hezel 2019년 8월 14일
편집: Stephen23 2019년 8월 16일
I am using a sensor which updates time information at 1Hz, but samples data at 1kHz. Therefore I have a time array like so:
t_old =
if the collect was n seconds long. I would like 999 other time stamps in between the already existing ones. So the result ought to be
t_new =

답변 (2개)

Adam Danz
Adam Danz 2019년 8월 14일
편집: Adam Danz 2019년 8월 16일
Set the 'resampleRate' to 1000 if you want [1,2] to become [1.001, 1.002, ... 2.999].
'timestamps' is your original vector.
resampleRate = 1000;
timestamps = 1:10; %must be a vector
timeStampsResampled = reshape((timestamps(:) + linspace(0,1-1/resampleRate,resampleRate)).',1,[]);

Stephen23
Stephen23 2019년 8월 16일
편집: Stephen23 2019년 8월 16일
>> t_old = 1:10; % times 1:N
>> rate = 1000; % 1 kHz
>> t_new = linspace(t_old(1),t_old(end),(numel(t_old)-1)*rate+1);

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