For loop within for loop
이전 댓글 표시
Please help me out. This code isn't working...
qq=8:10008;
for m = 1:9
for n = 1:10001
A(m, n) = (m+n)+qq;
end
end
I just want answer for A
댓글 수: 3
No idea what answer you want since you didn't tell us and you already said the code isn't working so there's not much point us looking at that to understand what you want.
However, you are adding a vector, qq, to a scalar (m+n) and trying to assign the result of this to a scalar A(m,n) which clearly will not work. At a guess you want to add qq(n) instead.
DARLINGTON ETAJE
2019년 8월 8일
Alex Mcaulley
2019년 8월 9일
편집: Alex Mcaulley
2019년 8월 9일
You can do it without loop. For example:
qq = 8:10008;
n = 1:10001;
m = 1:9;
[X,Y] = meshgrid(qq + n,m)
A = X + Y;
If you use the loops, at least preallocate your array A to minimize the execution time:
qq = 8:10008;
A = zeros(9,10001);
for m = 1:9
for n = 1:10001
A(m, n) = (m+n)+qq(n);
end
end
답변 (1개)
Jos (10584)
2019년 8월 9일
In recent ML versions there is no need for meshgrid or so. The plus syntax will expand the vectors :-)
% a smaller example
n = 1:11
m = 1:4
q = 8:18
A = m' + n + q
카테고리
도움말 센터 및 File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기
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