How to declare variables in a function

조회 수: 1 (최근 30일)
Blue
Blue 2019년 8월 1일
댓글: Adam Danz 2019년 8월 1일
Hi,
I am curious as to why the variables 'user' and 'pass' are not recognized by Matlab in the following snippet. When the user launches the function, Matlab throws a undefined function or variable 'pben' where pben is the input from the user.
function update_table(user, pass)
% Info
username = user;
password = pass;
datasource = 'SGDOP';
% Connection and SQL query
conn = database(datasource, username, password);
sqlquery = ['SELECT * from table x'];
data = fetch(conn, sqlquery);
save('data.mat', 'data')
end
  댓글 수: 4
Blue
Blue 2019년 8월 1일
Hi,
I am launching the function as update_tabel(pben, aaaa) where pben is the user and aaaa would be the password. Then the user and password are used to establish the connection to a database.
Adam Danz
Adam Danz 2019년 8월 1일
My bet is that when you call update_tabel(pben, aaaa), pben is not defined.

댓글을 달려면 로그인하십시오.

채택된 답변

Steven Lord
Steven Lord 2019년 8월 1일
My guess is that you're trying to call this function like:
update_table(pben, somePassword)
That attempts to pass the contents of the variable named pben or the result of calling a function named pben with 0 input arguments and 1 output argument into update_table. If you want to pass the literal text pben into the function, you need to specify it as a char vector or as a string.
update_table('pben', somePassword)
update_table("pben", somePassword)
If your password is not stored in a variable named somePassword but is the literal text somePassword, you need to pass that in as text as well.
update_table('pben', 'somePassword')
update_table("pben", "somePassword")
  댓글 수: 1
Blue
Blue 2019년 8월 1일
Ah. That was embarrasingly simple. Thank you.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Database Toolbox에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by