How to add new elements in a big array

I want to repeat this procedure for NT = 1e4 trials, storing the N-value for each trial in a 1e4 element array, and report the median number. how to make every iteration's length of the group gets added to the N array that I created the zeros syntax? I want just one array of NT elements at the end.

N = zeros(1,NT);
        for j = 1:NT
            % while loop for recycling the match of birthdays in the same week.
            matchFound = 0;
            k = 0; group = ceil(365*rand);
            while matchFound == 0 && k <= NT
              k = k + 1;
              newBD = ceil(365*rand);
                  % if conditioning a group with birthdays in the same week.
                  if abs(newBD - group(k)) < 7 ...
                     || abs(newBD - group(k) - 365) < 7 ...
                     || abs(newBD - group(k) + 365) < 7
                     matchFound = 1;
                     fprintf('The required number of people is %i\n', length(group))
                     N = length(group);
                  end
              % New Birthday groups upon each new addition of a person.
              newG = [group; newBD];
              group = newG;
            end
        end
        fprintf('Median Number of People %i ', median(N))
end

Answer 1

[James Tursa]

Maybe assign into elements of N with indexing:

N(j) = length(group);

[Mina Mansour]

Where exactly do I assign N(j)?

[James Tursa]

I would assume the same place you are assigning it now. Just change the left hand side from N to N(j).

[Mina Mansour]

Thank You it worked!