solve a system of equations symbolically with R2018a

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Katy Skillings
Katy Skillings 2019년 7월 16일
댓글: Walter Roberson 2019년 7월 17일
>> eqn1='(Fa0*x1)/0.1*(9.05*(1-x1))*(27.8-9.05*x1))==3785'
eqn1 =
'(Fa0*x1)/0.1*(9.05*(1-x1))*(27.8-9.05*x1))==3785'
>> eqn2='(Fa0*(x2-x1))/0.1*(9.05*(1-x2))*(27.8-9.05*x2))==3785'
eqn2 =
'(Fa0*(x2-x1))/0.1*(9.05*(1-x2))*(27.8-9.05*x2))==3785'
>> eqn3='(Fa0*(0.95-x2))/0.1*(9.05*(1-0.95))*(27.8-9.05*0.95))==3785'
eqn3 =
'(Fa0*(0.95-x2))/0.1*(9.05*(1-0.95))*(27.8-9.05*0.95))==3785'
>> solT=solve(eqn1,eqn2,eqn3,x1,x2,Fa0)
Error using solve>getEqns (line 418)
List of equations must not be empty.
Error in solve (line 226)
[eqns,vars,options] = getEqns(varargin{:});

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답변 (1개)

Walter Roberson
Walter Roberson 2019년 7월 16일
You are using R2018b or later. solve() no longer accepts character vectors for equations.
Furthermore, each of your equations has an extra ) before the ==
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Katy Skillings
Katy Skillings 2019년 7월 17일
Thank you. I attempted solving another way and got this answer as well but was intimidated by the lengthy answer. What is vpa?

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