How can I solve a nonlinear model using Newton Raphson ?

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Mallouli Marwa
Mallouli Marwa 2019년 7월 15일
댓글: Mallouli Marwa 2020년 1월 25일
Hi
How can I solve this nonlinear model using Newton Raphson ?
x1 +x2^2 +cos (x3) = 2
x1 +sin (x2) + x3^3 = 1
x3 +x2^3+x3^3 = 4

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Stephan
Stephan 2020년 1월 25일
One way:
result = fsolve(@fun,[1 1 1])
function F = fun(x)
F(1) = x(1) + x(2).^2 + cos(x(3)) - 2;
F(2) = x(1) + sin(x(2)) + x(3).^3 - 1;
F(3) = x(3) +x(2).^3 + x(3).^3 - 4;
end
gives:
Equation solved.
fsolve completed because the vector of function values is near zero
as measured by the value of the function tolerance, and
the problem appears regular as measured by the gradient.
<stopping criteria details>
result =
-0.5583 1.3732 0.8329
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John D'Errico
John D'Errico 2020년 1월 25일
The best way to solve it. Don't use Newton-Raphson at all. :)
Mallouli Marwa
Mallouli Marwa 2020년 1월 25일
If I want to use Newton Raphson.
How can we change it ?

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