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same input output signal name in simulink

조회 수: 14 (최근 30일)
TaeHee Kwun
TaeHee Kwun 2019년 7월 12일
댓글: sreedevi 2021년 6월 13일
I want to make code below by model (or stateflow) using Code Generation
if( var > 10){
var = 10;
}
In this case, upper 'var' is input of chart(or subsystem) and lower 'var' is output of chart.
So, it occurs signal complication if I use same variables name or I can't make same name of chart's input and output.
I can make this if sentance by using two variables, but I hope to make this by using one.
Thanks for your help.
Sincerely,
TaeHee Kwun.

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Phani Teja
Phani Teja 2019년 7월 16일
편집: Phani Teja 2019년 7월 16일
Yeh It can be possible with Data store memory block.
Make a Variable 'Var' in stateflow and change its scope to Data store memory .
You can also control the variable storage class by resolving data store memory with simulink signal.
The generated code looks like:
/* Real-time model */
RT_MODEL_Chart_T Chart_M_;
RT_MODEL_Chart_T *const Chart_M = &Chart_M_;
/* Model step function */
void Chart_step(void)
{
/* Chart: '<Root>/Chart' */
/* Re-use inputs */
if (Var > 10) {
/* NEW_PATTERN */
Var = 10;
}
/* End of Chart: '<Root>/Chart' */
}
  댓글 수: 2
TaeHee Kwun
TaeHee Kwun 2019년 7월 20일
Thanks for your answer!
But, I can't still understand how to make this blocks...
If you can, can you upload some of your blocks?
Thanks.
sreedevi
sreedevi 2021년 6월 13일
Hi ,Did you get an answer for the question.If yes please post it

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