Comparing an array of cells in a matrix
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Hello! I need to compare values with each other in cell arrays
for redit = 1:length(xintegra)-1
if EE1{redit}-100>= EE1{redit+1};
E1{redit}=0;
else EE1{redit}+100 <= EE1{redit+1};
E1{redit}=EE1{redit};
end
end
You give an error "Index exceeds matrix dimensions."
Help me fix
댓글 수: 2
Rik
2019년 7월 9일
Reply by Lev Mihailov:
the minimum value of my matrix = 11003, EE1 this is an indicator of where it is located.
답변 (1개)
Roy Kadesh
2019년 7월 9일
If you want loop through all values of EE1, then you can use the code below.
for redit = 1:numel(EE1)-1
if EE1{redit}-100>= EE1{redit+1}
E1{redit}=0;
elseif EE1{redit}+100 <= EE1{redit+1} %did you mean elseif?
E1{redit}=EE1{redit};
end
end
If you want to catch the case where redit is larger than the numer of elements in EE1, you can fill in the code below.
for redit = 1:numel(xintegra)-1
if (redit+1)>numel(EE1)
%do something else
else
if EE1{redit}-100>= EE1{redit+1}
E1{redit}=0;
elseif EE1{redit}+100 <= EE1{redit+1} %did you mean elseif
E1{redit}=EE1{redit};
end
end
end
댓글 수: 1
Rik
2019년 7월 9일
If there are indeed only numeric values inside that cell array, it is probably much faster to convert it to a double and use logical indexing to create the output.
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