i get an error.whats wrong? why the values of 'B' in intger instead of decimal.

II=[14 23;44 15];

R=II(:)';

x=0.3;

p=0.343;

for n=2:4;

if x(n-1)>=0 & x(n-1)<=p

x(n)=x(n-1)/p;

else

x(n)=(1-x(n-1))/(1-p);

end

end

A=sort(x);

[A,T]=sort(x);

Y=R(T);

C=reshape(Y,[2,2]);

r = 3.8;

L(1)= 0.234;

for i=2:4

L(i) = r*L(i-1)*(1-L(i-1));

end

mm=min(L);

nn=max(L);

oo=nn-mm;

Z=uint8(8*((L-mm)/oo))+1;

%for i=1:9

%K(i)=mod((abs(L(i))-floor(abs(L(i))))*1e14,50);

%end

CC(1)=bitxor(mod(157,50),mod(Y(1)+Z(1),50));

for i=2:4

CC(i)=bitxor(mod(CC(i-1),50),mod(Y(i)+Z(i),50));

end

ZZ=reshape(CC,[2,2]);

B=ZZ/10

why the value of B in intger.?

Answer 1

[KALYAN ACHARJYA]

See your zz data is integer type (uint8).

>> whos ZZ
  Name      Size            Bytes  Class    Attributes

  ZZ        2x2                 4  uint8   

Hence

ZZ =
  2×2 uint8 matrix

   31   18
   10   35

Now ZZ/10

B =
  2×2 uint8 matrix
   3   2
   1   4

Souce stackoverflow{dor}com: Converting both integer values to a double precision value will ensure that MATLAB performs floating point division instead of integer division (which will round off the result). See this link

But when you convert zz to double

   B=double(ZZ)/10
   format shortg

See the results

   B =

          3.1          1.8
            1          3.5

[Sultan Mehmood]

thanku

[Stephen23]

The MATLAB documentation explains the expected output classes for operations on integers:

https://www.mathworks.com/help/matlab/matlab_prog/integers.html