How to take all output from while loop?
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I have while loop in following coding. it count data for a year. i am no able to take all one year data. It just shows last answer. I also tried double command it doesn't work too. Please help me how to take all one year data.
Thanks in advance.
clc;
clear;
clear all;
pv = xlsread('POWER PV');
p = size (pv,1);
load = xlsread('LOAD');
pemfc = xlsread('PEMFC 1');
l = size (pemfc,1);
i = 243.72; %(731 Wh)
h2 = 11698.56; %(48 Saat için h2 depolama)
for sun = 1:1:p ;
if load(sun,1) < pv (sun,1);
x = pv(sun,1)-load (sun,1);
elseif load(sun,1) > pv (sun,1);
y = load(sun,1) - pv (sun,1);
v = pemfc(find( pemfc > y(:,1) , 1 ) ); % very important .....
x = -v ;
while h2 > 0
g = h2 + (x(sun,1)*(243.71/731));
h2 = g;
h2;
end
else
x = 0;
end
n(sun,1) = double (x);
end
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Star Strider
2019년 7월 7일
I cannot run your code without your files.
However see if this solves the problem with your while loop:
k = 1;
while h2 > 0
g = h2 + (x(sun,1)*(243.71/731));
h2 = g;
h2v(k) = h2;
k = k + 1;
end
or, if ‘h2’ is not a scalar, save it as a cell array:
k = 1;
while h2 > 0
g = h2 + (x(sun,1)*(243.71/731));
h2 = g;
h2v{k} = h2;
k = k + 1;
end
Experiment to get the result you want.
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Mohammad Sulaiman Stanekzai
2019년 7월 8일
편집: Mohammad Sulaiman Stanekzai
2019년 7월 8일
Star Strider
2019년 7월 8일
If my previous code did not do what you want, I have no idea what the problem is. I have no other solutions. I do not have your data, or an example of what you want the result to be.
Guessing here.
Perhaps this is what you want:
elseif load(sun,1) > pv (sun,1);
y = load(sun,1) - pv (sun,1);
v = pemfc(find( pemfc > y(:,1) , 1 ) ); % very important .....
x = -v ;
if h2 > 0
g = h2 + (x(sun,1)*(243.71/731));
h2 = g;
h2v(sun) = h2;
end
else
It replaces your while loop with an if block.
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