n+1 in formula

Hi, could someone help me to put the next formula in matlab?

The sum goes to n-1: 1/2*T* sum(abs(AP[n+1]*ML[n] - AP[n]*ML[n+1])).

The main problem is the n+1 how can i do this.

[Raj]

Your question is not at all clear. Please see this:

https://in.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer

[Stephen23]

B's "Answer" moved here:

Is this better? AP and ML are about the x and y coordinates when someone is standing still.

[Raj]

" main problem is the n+1 " I am still not quite sure what is the problem. Is this what you are looking for?

count=0;
for n=1:N-1
count=count+abs((AP(n+1)*ML(n))-(AP(n)*ML(n+1)));
end
count=(0.5*count)/T;

Answer 1

[Dheeraj Singh]

Hi,

I understand that by “put” you mean you want to implement it without using loops.

The following code implements the above formula without using loops using random values of “AP” and “ML”

T=2;
n=100
AP=rand(n,1);
ML=rand(n,1);
i=1:n-1;
j=i+1;
val=sum(abs(AP(j).*ML(i)-AP(i).*ML(j)))/(2*T)