Simulink model of the same is attached here.
Forward and Inverse Kinematics for robot
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Hello,
Hope you are doing well.
I am verifying the output of my forward kinematics through inverse kinematics and the results are not as desired. As the output of my inverse kinematics is not coming out to be the same as the input of forward kinematics.
The D-H parameters of manipulator is given as:
alpha a theta d
Link 1 -90 0 theta1* d1
Link 2 0 a2 theta2* 0
Link 3 0 a3 theta3* 0
Functions used are:
Forward kinematics:
function ph = forward_kinematics(q)
%input: [q1 q2 q3]
l2 = 0.28;
l3 = 0.2;
d1 = 0.03;
q1 = q(1);
q2 = q(2);
q3 = q(3);
ph = zeros(3,1);
ph1 = l2*cos(q1)*cos(q2)+l3*cos(q1)*cos(q2+q3);
ph2 = l2*sin(q1)*cos(q2)+l3*sin(q1)*cos(q2+q3);
ph3 = d1-l2*sin(q2)-l3*sin(q2+q3);
ph=[ph1;ph2;ph3];
end
Inverse kinematics
function q = inv_kinematics(ph)
%input: [ph1 ph2 ph3]
l1 = 0.05;
l2 = 0.28;
l3 = 0.2;
d1 = 0.03;
ph1 = ph(1);
ph2 = ph(2);
ph3 = ph(3);
r=sqrt(ph1^2+(ph3-d1)^2);
alpha=acos((r^2+l2^2-l3^2)/(2*r*l2))
q = zeros(3,1);
q1=atan2(ph2,ph1);
q2=atan2(ph1,ph3-d1)-alpha;
q3=atan2(ph1-l2*sin(q2),ph3-d1-l2*cos(q2))-q2;
q=[q1;q2;q3];
end
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답변 (3개)
Mohd Musharaf Hussain Sarwari
2021년 2월 13일
I WANT SCARA ROBOT forward-and-inverse-kinematics MATLAB CODE
댓글 수: 3
Umar
2024년 9월 8일
Hi @Mohd Musharaf Hussain Sarwari,
You mentioned, “ I WANT SCARA ROBOT forward-and-inverse-kinematics MATLAB CODE”
Please refer to this link which should help resolve your problem. https://www.mathworks.com/matlabcentral/fileexchange/128529-inverse-kinematics-of-scara-robot
Krishna Akella
2019년 6월 28일
Hi Mohsina,
I don't know the answer to your question but I looked at your model and I have a few observations. In your model I assume the inputs to your forward kinematics function are the joint angle values and the output is the end effector location. And I assume the inputs to your inverse kinematics function is the end effector location and the outputs are the joint values.
If this is correct, then why would you not pass the output from forward kinematics back to your inverse kinematics function to validate that you are getting back the same joint values?
I made this change and it seems like the first output value matches.
The reason the other joint angles might still not be matching is because you could have multiple solutions to worry about. For example, in the computation of your inverse kinematics function, you have
r = sqrt(ph1^2+(ph3-d1)^2);
There could be two solutions to the sqrt function. A positive and a negative value. And MATLAB returns the positive value. Similar thing is true for other functions like acos, where multiple angles can give the same result. All these will result in multiple solutions to result in the same end effector location.
Regards,
Krishna
Ram Bodhe
2020년 5월 12일
function q = inv_kinematics(ph)
%input: [ph1 ph2 ph3]
l1 = 0.05; l2 = 0.28; l3 = 0.2; d1 = 0.03;
ph1 = ph(1); ph2 = ph(2); ph3 = ph(3);
r=sqrt(ph1^2+(ph3-d1)^2); alpha=acos((r^2+l2^2-l3^2)/(2*r*l2))
q = zeros(3,1); q1=atan2(ph2,ph1); q2=atan2(ph1,ph3-d1)-alpha; q3=atan2(ph1-l2*sin(q2),ph3-d1-l2*cos(q2))-q2;
q=[q1;q2;q3];
end
댓글 수: 2
Umar
2024년 9월 8일
Hi @Ram Bodhe ,
I executed your code and got error message "Not enough input arguments" which indicates that the function is being called without the required input vector ph. To resolve this issue, you need to make sure that the function is called with the appropriate input. Additionally, enhance the function to include input validation, ensuring that the input is a three-element vector. Here is the corrected and updated version of the inv_kinematics function:
function q = inv_kinematics(ph) % Check if the input is a 3-element vector if nargin < 1 || length(ph) ~= 3 error('Input must be a 3-element vector [ph1, ph2, ph3].'); end
% Define the lengths of the robotic arm segments l1 = 0.05; l2 = 0.28; l3 = 0.2; d1 = 0.03;
% Extract the position components from the input vector ph1 = ph(1); ph2 = ph(2); ph3 = ph(3);
% Calculate the radius and angle for the inverse kinematics r = sqrt(ph1^2 + (ph3 - d1)^2); alpha = acos((r^2 + l2^2 - l3^2) / (2 * r * l2));
% Initialize the joint angles vector q = zeros(3, 1);
% Calculate the joint angles using inverse kinematics equations q1 = atan2(ph2, ph1); q2 = atan2(ph1, ph3 - d1) - alpha; q3 = atan2(ph1 - l2 * sin(q2), ph3 - d1 - l2 * cos(q2)) - q2;
% Combine the joint angles into a single output vector q = [q1; q2; q3]; end
Explanation of Changes Made
Input Validation: The function now checks if the input ph is provided and whether it contains exactly three elements. If not, it raises an error with a descriptive message. This prevents the function from executing with invalid inputs.
Code Structure: The overall structure of the code remains intact, ensuring that the calculations for the joint angles are preserved.
Comments: Additional comments have been added to clarify each step of the process, making the code more understandable for future users or developers.
Now, to utilize the inv_kinematics function, you can call it with a three-element vector representing the desired position of the end effector. For example:
% Define the desired position desired_position = [0.1, 0.2, 0.15];
% Call the inverse kinematics function joint_angles = inv_kinematics(desired_position);
% Display the results disp('Calculated Joint Angles (radians):'); disp(joint_angles);
Please see attached.
When you will run the above example with a valid input vector, the function will compute and display the joint angles required to position the robotic arm at the specified coordinates. Hope, this answers your question.
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