Consider the following example. a and b are two random variables. The loop will exit if and only if a+b=1. Is it true or false?
a=rand;
b=rand;
while(a+b == 1)
a=rand;
b=rand;
end

댓글 수: 1

Sabarinathan Vadivelu
Sabarinathan Vadivelu 2012년 8월 27일
I found that sometimes the sum was exceeding 1 or less than 1. Why?

댓글을 달려면 로그인하십시오.

 채택된 답변

Walter Roberson
Walter Roberson 2012년 8월 27일

0 개 추천

While executes as long as the given condition is true, so the loop would only execute as long as the sum was 1.

댓글 수: 5

Sabarinathan Vadivelu
Sabarinathan Vadivelu 2012년 8월 27일
편집: Sabarinathan Vadivelu 2012년 8월 27일
But sir, I found that when adding both values I'm getting a value greater than 1.
a=0.7849 and b=0.9728. this value I got one time.
Walter Roberson
Walter Roberson 2012년 8월 27일
If the sum was greater than 1, then a+b == 1 would be false, so your loop as written would not execute, so the values would be left unchanged.
Sabarinathan Vadivelu
Sabarinathan Vadivelu 2012년 8월 27일
How can I overcome this problem? How to satisfy that condition? It should be a +b = 1. No other values should come.
Jan
Jan 2012년 8월 27일
편집: Jan 2012년 8월 27일
If a+b must be 1, simply use:
a = rand; b = 1 - a;
It is extremely unlikely that two random numbers will have a sum of 1. I think the probability is in the magnitude of 10^-53. Therefore rejecting the values until the sum equals 1 will take a looong time.
a=rand;
b=rand;
while(a+b ~= 1)
a=rand;
b=rand;
end

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Electrical Block Libraries에 대해 자세히 알아보기

제품

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by