How to resolve the "Index exceeds matrix dimensions" error ?

if true
  data = getdata(vid,50,'double','cell');
  for i=1:5:100
    data{i}(:,:,1)=(data{i}(:,:,1))+(data{i+1}(:,:,1))+(data{i+2}(:,:,1))+ ...
                   (data{i+3}(:,:,1))+(data{i+4}(:,:,1))/5;
    data{i}(:,:,3)=(data{i}(:,:,3))+(data{i+1}(:,:,3))+(data{i+2}(:,:,3))+...
                   (data{i+3}(:,:,3))+(data{i+4}(:,:,3))/5;
    data{i}(:,:,2)=(data{i}(:,:,2))+(data{i+1}(:,:,2))+(data{i+2}(:,:,2))+...
                   (data{i+3}(:,:,2))+(data{i+4}(:,:,2))/5;
  end
end

[EDITED, Jan, code formatted - Please do this by your own, thanks!]

Answer 1

[Dishant Arora]

dbstop if error

use this before executing,u will get an idea where exactly this error occurs

[sadhna]

no its not work

[Dishant Arora]

 data = getdata(vid,50,'double','cell');

from this what i conclude is that you have 50 samples/elemesnts in cell array data. and indices in your code goes above 50 and that results in error. you should once again take look at the loop and reassign i.

[Jan]

@sadhna: "it's not working" is not helpful for us. Please explain all necessary details, e.g. the line which causes the error, the size of the processed array and the value of i. Finally these informations should allow you to solve the problem by your own.

[sadhna]

??? Index exceeds matrix dimensions.

Error in ==> lol2 at 38 data{i+1}(:,:,1)=(data{i}(:,:,1)+data{i+5}(:,:,1))/2;

[Ryan]

If I had to guess, data{101} through data{104} do not exist and you'll need to stop your loop sooner. What is the size of data?

[sadhna]

if true data = getdata(vid,50,'double','cell'); for i=1:5:100 for i=1:5:50 data{i+1}(:,:,1)=(data{i}(:,:,1)+data{i+5}(:,:,1))/2; data{i+1}(:,:,2)=(data{i}(:,:,2)+data{i+5}(:,:,2))/2; data{i+1}(:,:,3)=(data{i}(:,:,3)+data{i+5}(:,:,3))/2; end

ERROR Index exceeds matrix dimensions.

Error in ==> lol2 at 38 data{i+1}(:,:,1)=(data{i}(:,:,1)+data{i+5}(:,:,1))/2;

[Jan]

Ok, I assume that this is the line, which causes the problem. Correct? What is the value of "i"? What is the size of "data{i}" and "data{i+5}". Come on, Sadhna, start to debug your code and show some effort to solve your problem.

[sadhna]

i cant understand how to solve this prob ..plz help me out of this...

[Dishant Arora]

change the loop form 1 to 50

for i=1:5:50

Answer 2

[serena dsouza]

Hi, I am getting same error in this following loop but on selected samples , even though they are of same length, Only Some of them giving error. Here, I am trying to do framing of audio signal.Can anyone help me in this.Thank you.

n=round(length(xOut)/no_frames); %find how many samples will each frame contain
P=zeros(n,no_frames); 
for j=0:no_frames-1
    P(:,j+1)=xOut(1+n*j:n*(j+1));
end

Answer 3

[maryam ahmad]

Hi i want to 3D plot of x, y anad z and for that i have table of 1000x1 (name 'Rouser1') and have 3 variables as following

    x(n) = seq (n)-seq (n-1);
    y(n) = seq (n-1) - seq (n-2);
    z(n) = seq (n-2) - seq (n-3);
% in this seq will be  the 'values of Rouser1' and Variable of Rouser1 is 'VarName1'
% so how im suppose to make a 3D plot?