Sorting through labelled data

Given the data of two columns below with negative and positive label

    '0,Negative'
    '1,Negative'
    '1,Positive'
    '2,Negative'
    '2,Positive'
    '3,Positive'
    '4,Negative'
    '4,Positive'
    '5,Positive'
    '9,Positive'

Please I want to use the code below to sort for negative or positive numbers instead of even and odd numeric data example code below

for col = 1:size(croppedz, 2) 
%sort even/odd rows, reshape each into a Kx? matrix, sum across rows and divide the two sums
% K = can be anynumber that groups it
result(:, col) = sum(reshape(sort(croppedz(1:2:end, col)), K, []), 1) ./ sum(reshape(sort(croppedz(2:2:end, col)), K, []), 1); 
end        
end

Thanks for your help in advance

Tino

Answer 1

[KSSV]

str = { '0,Negative'
    '1,Negative'
    '1,Positive'
    '2,Negative'
    '2,Positive'
    '3,Positive'
    '4,Negative'
    '4,Positive'
    '5,Positive'
    '9,Positive'} ;

% Get positive 
idx = contains(str,'Positive') ; 
str(idx)

[Tino]

Thanks for your swift anwser KSSV

how do I seperate the values from the character to get a different cell for positives and negatives

Thanks in advance

[KSSV]

str = { '0,Negative'
    '1,Negative'
    '1,Positive'
    '2,Negative'
    '2,Positive'
    '3,Positive'
    '4,Negative'
    '4,Positive'
    '5,Positive'
    '9,Positive'} ;

V = regexp(str,'\d+','match') ;
V = [V{:}] ; 
iwant = cellfun(@str2num,V')

Answer 2

[Priysha Aggarwal]

If you can skip using the above given for loop, you can store the above strings in a string array as :

A = ["0","Negative";

"1","Positive";

...];

Now you can sort A according to column 2:

[mat,idx] = sort(A(:,2)); % this will sort 'negative' and 'positive' labels alphabetically

sortedA = A(idx,:); %sorting column 1 accordingly