Multiply Image Pixels by a Matrix

조회 수: 9 (최근 30일)
Royi Avital
Royi Avital 2012년 8월 22일
Hello, Let's say I have a 3 channel image M -> [numRowx * numColumns * numChannels]. I also have a 3 by 3 matrix A (Color Conbersion).
I would like to multiply each pixel 3 channel by the matrix to have a new 3 channels pixel.
How would you do that the most efficient way without writing the actual formula by hand (Multiplying each channel of the image by a row)?
My best so far is:
rgbToYPbPrMat = [0.299, 0.587, 0.144; 0.5, -0.419, -0.081; -0.169, -0.331, 0.5];
yPbPrToRgbMat = inv(rgbToYPbPrMat);
inputImage = randi([0, 255], [256, 256, 3], 'uint8');
inputImageFP = double(inputImage) / 255; %<! Floating Point
figure;
image(inputImage);
axis image;
inputImageYPbPrFP = shiftdim(reshape((rgbToYPbPrMat * reshape(shiftdim(inputImageFP, 2), [3, (256 * 256)])), [3, 256, 256]), 1);
Thanks.
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Royi Avital
Royi Avital 2012년 8월 22일
Hi @Sean, Look at my code I added.
I couldn't make it work with 'bsxfun'.
Royi Avital
Royi Avital 2012년 8월 23일
Anyone? Please...

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Jan
Jan 2012년 8월 23일
I cannot check it currently, but please try:
M = rand(numRows, numColumns, 3);
T = rand(3, 3);
P = reshape(M, numRows * numColumns, 3) * T';
Result = reshape(P, numRows, numColumns, 3);
  댓글 수: 1
Royi Avital
Royi Avital 2012년 8월 23일
Hi, Checked it, it does work and it the fastest so far (Since the Transpose works on the smaller matrix).
Do you think there's even a faster way?
Thanks.

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