one program has different results in different versions
이전 댓글 표시
Here is the code:
C=0.3+0.5i;
V = linspace(-2.0,2.0,400);
[Re,Im] = meshgrid(V);
Z = Re + i * Im;
B = 0;
for K = 1:100
B = B+(abs(Z)<=2);
Z = Z.*Z + C;
end;
imagesc(B);
colormap(jet);
axis equal
In 2018a, the result is:

But, in 2015b, the result is:

Why this will happen? How can I get the second figure in 2018a version? Thank you very much.
댓글 수: 4
Star Strider
2019년 5월 27일
For what it’s worth, I get the R2015b result in R2019a.
the cyclist
2019년 5월 27일
I get your R2015b result with R2018b. Maybe a bug was introduced between R2015b and R2018a, which was fixed in R2018b?
per isakson
2019년 5월 27일
I get your R2015b image with both R2018a and R2018b.
Walter Roberson
2019년 5월 27일
Fractal in R2016b, R2017b, R2018a, R2018b, R2019a on Mac
Do you just happen to have an AMD cpu?
답변 (1개)
Steven Lord
2019년 5월 27일
In release R2018a did you assign a value to the variable i before running that code? When you want to ensure that you're using the square root of -1 you should always use 1i. Try replacing your line:
Z = Re + i * Im;
with
Z = Re + 1i * Im;
댓글 수: 1
per isakson
2019년 5월 27일
편집: per isakson
2019년 5월 27일
Yes adding i=1;
%%
i = 1;
C=0.3+0.5i;
etc.
did it

on R2018b
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