I'd like to get the index (i) for wich the condition I set in the foor loop appears on the results
Fm0= linspace(0.01,0.02,100);
%ciclo iterativo
for i=1:100
for Fm= (0.25).*(((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1))))).^-1).*((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1)))))).^-1)
if Fm(i)-Fm0<=10^-6
break
end
end
end

 채택된 답변

Walter Roberson
Walter Roberson 2019년 5월 18일

0 개 추천

Fm0 = linspace(0.01,0.02,100);
Fm= (0.25).*(((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1))))).^-1).*((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1)))))).^-1)
i = find( Fm-Fm0 <= 10^-6, 1);
You will find that the answer is 1 -- Fm0(1) > Fm(1) so the subtraction is negative and so satisfies the condition.
You might perhaps have been thinking,
i = find( abs(Fm-Fm0) <= 10^-6, 1);
but you will find that this is empty.

댓글 수: 2

Franco Belletti
Franco Belletti 2019년 5월 19일
thanks!
If you are looking for the value of Fm such that
Fm = (0.25).*(((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm).^-1))))).^-1).*((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm).^-1)))))).^-1)
then the value turns out to be complex, at least for positive Rey (I did not experiment with negative Rey.)

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Mathematics에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by