Is there a way to dynamically save a plot figure into a jpeg file without having to type the filename i would be saving it into?
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I am executing a code that generates a plot figure, which I save using the following command: print '-djpeg' '-f2' '-r300' _f2
Where _f2 is literally the name of the jpeg I will be saving my plot into.
I wonder if there's a way of doing this dynamically, what i mean is that instead of entering the file name literally I could pass a string containing the file name, so I can execute this could without having to type each time the file name in my code.
As a previous step to generating the plot figure, I load a file and analyze it. Each file is identified with a frequency (filename=06000). My idea is to copy the filename (06000) into a string, so i can identify each jpeg with its corresponding file (06000.jpeg)
Thanks!!
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Image Analyst
2012년 8월 18일
편집: Image Analyst
2012년 8월 18일
Use sprintf() to construct your filename and then use export_fig() to save it:
baseFileName = sprintf('F%s_h%s.jpg', numberId, numberId);
fullFileName = fullfile(yourFolder, baseFileName);
export_fig(figureHandle, fullFileName); % Best way.
saveas(figureHandle, fullFileName); % Alternative way
댓글 수: 2
Laura
2012년 8월 18일
Image Analyst
2012년 8월 18일
It look like you just ran the code and didn't read the FAQ. In the FAQ it explains how you can download export_fig. Anyway, here is the direct link: http://www.mathworks.com/matlabcentral/fileexchange/23629-exportfig Or you can go to the front page of the File Exchange: http://www.mathworks.com/matlabcentral/fileexchange/ because it's always the most downloaded submission every month.
Jürgen
2012년 8월 18일
1 개 추천
Hi,
with e.g.: freq=1 time=103 Filename = ['F' num2str(freq) '_h' num2str(time) '.jpg'] =>Filename =F1_h103.jpg then saveas(gcf, Filename)
this should work
regards,J
댓글 수: 5
Laura
2012년 8월 18일
Jürgen
2012년 8월 21일
Hi then it is easier, because you can use the string directly :
freq='1', time='103', Filename = ['F' freq '_h' time '.jpg'] then use the saveas
Laura
2012년 9월 3일
Sina Zinatlou
2021년 3월 24일
Image Analyst
2021년 3월 24일
That was from 9 years ago. Now you can use the new exportgraphics() function.
카테고리
도움말 센터 및 File Exchange에서 Creating, Deleting, and Querying Graphics Objects에 대해 자세히 알아보기
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