# could anyone help me to solve my question

조회 수: 1(최근 30일)
jaah navi 12 May 2019
댓글: gonzalo Mier 13 May 2019
As i am unable to get the answer i am asking it again.
I am having two matrices A=[0.6399 0.8965] and B=[ 0.7684 0.0120;
0.5333 0.9666;
0.0684 0.8322;
0.1996 0.4453]
of different sizes generated in my code.
when size(A) is lesser than size(B) i done with the following command line
code1:
[jj,kk]=size(A)
[jjj,kkk]=size(B)
zz=zeros(jjj,kkk)
zz(1:jj,1:kk)=A
C=B-zz
the code executes and gives me the result.
As A and B are generated by the code,sometimes size(A) is greater than size(B) so i have used the following command line
code2:
A=A(size(B,1),:)
social=B-A
the code executes and gives me the result.
As i doesnt know whether size(A) is greater or lesser than size(B) i need to use the above code 1 and code 2 together by using if condition.
Could anyone help me how to use if condition with respect to code 1 and code 2.

### 답변(1개)

gonzalo Mier 12 May 2019
You don't need if here. You can mix them as:
C = B;
len_A = min(size(B,1),size(A,1));
C(1:len_A,:) = C(1:len_A,:) - A(1:len_A,:);

#### 댓글 수: 1

gonzalo Mier 13 May 2019