calculating Kernel density for each column

Hi
Please how do I need a short code that will calculate the KDE of each column in the R.length data below
the KDE is given as = I/n*h sum ( K * (( v - i )/h) which is computed for each column
where h = 1.06 * variance * (n^(-0.2)) for each colum
n is the number of each column
i = first, second, third, fourth, fifth, sixth number of each column
v =pv is given as 3, 4, 5, 6 for each column
Thanks in advance
jonathan
R = [ 0.6164 3.4161 0.9950 3.4117;
3.1654 0.4123 4.2391 1.0198;
0.5745 3.0364 1.3191 3.1129;
2.9883 0.7348 3.8730 0.4123;
0.9381 3.3749 2.0421 3.5014;
2.1817 1.0630 3.0643 0.9487];

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Rik
Rik 2019년 4월 24일
What have you tried so far? Have a read here and here. It will greatly improve your chances of getting an answer.
David Wilson
David Wilson 2019년 4월 24일
Would ksdensity work? (From stats toolbox)
'Answer' by Jonathan Etumusei moved to comment and formatted:
This is what I have done so far and the answers are below
thanks
n = 6;
K = 3;
h1 = 1.06 * var(Z(:,1)) * (n ^ 0.2);
h2 = 1.06 * var(Z(:,2)) * (n ^ 0.2);
h3 = 1.06 * var(Z(:,3)) * (n ^ 0.2);
h4 = 1.06 * var(Z(:,4)) * (n ^ 0.2);
z1 = 1/ (n * h1);
z2 = 1/ (n * h2);
z3 = 1/ (n * h3);
z4 = 1/ (n * h4);
Ec11 = (K * (v1 - Z(1,1))/h1) ;
Ec12 = (K * (v1 - Z(2,1))/h1) ;
Ec13 = (K * (v1 - Z(3,1))/h1) ;
Ec14 = (K * (v1 - Z(4,1))/h1) ;
Ec15 = (K * (v1 - Z(5,1))/h1) ;
Ec16 = (K * (v1 - Z(6,1))/h1) ;
e1 = [Ec11; Ec12; Ec13; Ec14; Ec15; Ec16];
e1 = sum (e1);
Ec21 = K * (v2 - Z(1,2)/h2);
Ec22 = (K * (v2 - Z(2,2))/h2) ;
Ec23 = (K * (v2 - Z(3,2))/h2) ;
Ec24 = (K * (v2 - Z(4,2))/h2) ;
Ec25 = (K * (v2 - Z(4,2))/h2) ;
Ec26 = (K * (v2 - Z(4,2))/h2) ;
e2 = [ Ec21; Ec22; Ec23; Ec24; Ec25; Ec26];
e2 = sum (e2);
Ec31 = K * (v3 - Z(1,3)/h3);
Ec32 = (K * (v3 - Z(2,3))/h3) ;
Ec33 = (K * (v3 - Z(3,3))/h3) ;
Ec34 = (K * (v3 - Z(4,3))/h3) ;
Ec35 = (K * (v3 - Z(5,3))/h3) ;
Ec36 = (K * (v3 - Z(6,3))/h3) ;
e3 = [Ec31; Ec32; Ec33; Ec34; Ec35; Ec36];
e3 = sum (e3);
Ec41 = K * (v4 - Z(1,4)/h4);
Ec42 = (K * (v4 - Z(2,4))/h4) ;
Ec43 = (K * (v4 - Z(3,4))/h4) ;
Ec44 = (K * (v4 - Z(4,4))/h4) ;
Ec45 = (K * (v4 - Z(5,4))/h4) ;
Ec46 = (K * (v4 - Z(6,4))/h4) ;
e4 = [Ec41; Ec42; Ec43; Ec44; Ec45; Ec46];
e4 = sum(e4);
k = e1;
l = e2;
m = e3;
b = e4;
% the kernal density estimation
KDE1 = k * z1;
KDE2 = l * z2;
KDE3 = m * z3;
KDE4 = b * z4;
answer
-0.4881
-0.1668
-0.7734
-0.3972
Rik
Rik 2019년 4월 24일
Instead of using numbered variables, why don't you process the columns in a loop?
Tino
Tino 2019년 4월 24일
Yes but how do I do that ?

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Rik
Rik 2019년 4월 24일

0 개 추천

I am assuming the v values are the same as the column index, and that you made a mistake with the code for the second column.
Z = [ 0.6164 3.4161 0.9950 3.4117;
3.1654 0.4123 4.2391 1.0198;
0.5745 3.0364 1.3191 3.1129;
2.9883 0.7348 3.8730 0.4123;
0.9381 3.3749 2.0421 3.5014;
2.1817 1.0630 3.0643 0.9487];
n = 6;
K = 3;
z=zeros(1,size(Z,2));e=zeros(size(z));
for col=1:size(Z,2)
v=col;%is this what you mean?
h = 1.06 * var(Z(:,col)) * (n ^ 0.2);
z(col) = 1/ (n * h);
E = K * (v - Z(:,col))/h;
if col~=1
%did you mean for this to be different?
E(1)= K * (v - Z(1,col)/h);
end
e(col) = sum(E) ;
end
% the kernal density estimation
KDE = e .* z;

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Tino
Tino 2019년 4월 24일
Hi Rik
The v values are numbers obtained from a different computation below
strangeness1 = 0.25541
strangeness2 = 4.4465
strangeness3 = 0.38976
strangeness4 = 4.2112
using Si = [strangeness1,strangeness2, strangeness3, strangeness4];
% find the v-values
fnP=@(a,i)(sum(a(i)>a(1:i))+0.5*sum(a(i)==a(1:i)))/i;
Thanks in advance
Regards
Jonathan
Rik
Rik 2019년 4월 24일
Well, you know the inputs, you have working code, you should be able to integrate the calculation in my code. What issues are you having with that integration?

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