MATLAB plot not showing.
이전 댓글 표시
I tried plotting two graphs with the following:
with the following output:
The second one (plot(x,1./(4*x-8'))) is showing just fine, but not the first one (plot x,y1). Y1 is a 1x1001 double array. Why is that, and how can i fix the problem?
댓글 수: 3
Stephen23
2019년 4월 10일
@Micky Panleartkitsakul: we cannot run screenshots, we cannot edit screenshots, we cannot search screenshots. Please paste your code as text (formatted using the code button).
madhan ravi
2019년 4월 11일
Since the OP removed the orginal content according to the other question the content seems to be:
clear all ;
close all;
f=@(x,y1,y2) y2;
g=@(x,y1,y2) 1/4*y1-8;
%shooting method inntialization
initialize=[-5:.05:0];
for kk=1:length(initialize)
%delta x=1
x(1)=1;
y1(1)=10;
y2(1)=initialize(kk);
h=0.001;
x_initial=x(1);
xmaxvalue=2;
n=(xmaxvalue-x_initial)/h;
%runge kutta iterations using shooting method
for i=1:n
k0 = h*f(x(i),y1(i),y2(i));
l0 = h*g(x(i),y1(i),y2(i));
k1 = h*f(x(i)+(1/2)*h,y1(i)+(1/2)*k0,y2(i)+(1/2)*l0);
l1 = h*g(x(i)+(1/2)*h,y1(i)+(1/2)*k0,y2(i)+(1/2)*l0);
k2 = h*f(x(i)+(1/2)*h,y1(i)+(1/2)*k1,y2(i)+(1/2)*l1);
l2 = h*g(x(i)+(1/2)*h,y1(i)+(1/2)*k1,y2(i)+(1/2)*l1);
k3 = h*f(x(i)+h,y1(i)+k2,y2(i)+l2);
l3 = h*g(x(i)+h,y1(i)+k2,y2(i)+l2);
x(i+1) = x_initial+i*h;
y1(i+1) = double(y1(i)+(1/6)*(k0+2*k1+2*k2+k3));
y2(i+1) = double(y2(i)+(1/6)*(l0+2*l1+2*l2+l3));
end
yy1(kk)=y1(end);
end
p=interp1(yy1',initialize',1/4);
x(1)=1;
y1(1)=1/4
y2(1)=p;
h=0.001;
x_initial = x(1);
xmaxvalue=2;
n=(xmaxvalue-x_initial)/h;
for i=1:n
k0=h*f(x(i),y1(i),y2(i));
l0=h*g(x(i),y1(i),y2(i));
k1=h*f(x(i)+(1/2)*h,y1(i)+(1/2)*k0,y2(i)+(1/2)*l0);
l1=h*g(x(i)+(1/2)*h,y1(i)+(1/2)*k0,y2(i)+(1/2)*l0);
k2=h*f(x(i)+(1/2)*h,y1(i)+(1/2)*k1,y2(i)+(1/2)*l1);
l2=h*g(x(i)+(1/2)*h,y1(i)+(1/2)*k1,y2(i)+(1/2)*l1);
k3=h*f(x(i)+h,y1(i)+k2,y2(i)+l2);
k3=h*g(x(i)+h,y1(i)+k2,y2(i)+l2);
x(i+1)=x_initial+i*h;
y1(i+1)=double(y1(i)+(1/6)*(k0+2*k1+2*k2+k3));
y2(i+1)=double(y2(i)+(1/6)*(l0+2*l1+2*l2+l3));
end
%plot the solution
figure
title('shooting method')
xlabel('t')
ylabel('y(t)')
plot(x,y1)
hold on
% make your second plot
figure
(plot(x,1./(4*x-8)'))
legend('numerical solution','exact solution')
Rena Berman
2019년 5월 13일
(Answers Dev) Restored edit
답변 (2개)
Jon
2019년 4월 10일
The problem is that the second plot is replacing (overwriting) the first one in the figure window. If you open up a new figure, before making the second plot you will avoid this problem. Even better, create a new figure for each plot in case you already had another one there you didn't want to overwrite, So for example:
% make new figure
figure
% make the first plot
(plot x,y1)
% make another figure
figure
% make your second plot
(plot(x,1./(4*x-8')))
Also a couple of other side comments. I agree with Stephen's comment, it is better to use the code button to insert code. Also in your specific plot command, I'm not sure what you are intending with 4*x - 8'. In this case the transpose operator (') will only be applied to the scalar value of 8, which will not have any effect.
Pallavi Bharati
2020년 3월 10일
0 개 추천
My plot is not showing just axes are showing
카테고리
도움말 센터 및 File Exchange에서 Graphics Performance에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!