Deconvolution of a Convolved Gaussian and Expoential curve
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I would like to extract a decaying exponential curve from another curve that I already have, which is known to be the result of the convolution of a Gaussian and the pre-mentioned decaying exponetial.
The exact form of the exponential is unkown, but the form of the gaussian is known relatively well (i.e. amplitude, Full-width half maximum), and could be decsribed by your standard gaussian equation.
The already convoled data is also known, though it is relatively discreet, with uneven spacing (e.g. X = [0 1 5 10 20 100 200 500 1000])
I have tried using the "deconv" function available in matlab (https://uk.mathworks.com/help/matlab/ref/deconv.html) to hopefully get this exponential out, setting u to be the vector related to the already covolved data (whose length is the same as X), and v to the gaussian curve calculated at the already mentioned X positions (and hence is of the same length as u). However, it does not produce an exponential as hoped, and now at a loss of how to proceed.
Any suggestions or tips as to how I may be able to achieve this would be greatly appreciated. Thanks.
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Wenxuan Zheng
2019년 10월 24일
Hi, just wondering if you solved this cuz I am looking for the solution too :)
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John D'Errico
2019년 10월 24일
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As I recall from long ago, numeical deconvolution is a variation of a first kind integral equation.
The problem is, first kind integral equations can be difficult to solve because they amplify any noise in your data. This is called an ill-posed problem. Even tiny errors down in the least significant bits can be an issue.
And sadly, deconv is not able to handle non-uniformly spaced data. So you would need to write the code yourself.
The more information you can bring to the problem, the better off you will be. So, if you know the data arises as the convolution between a known gaussian and an unknown exponential, then it will be far easier on you than if you could do no more than assume the unknown function is say some general spline curve, to be then estimated. So if all you need to find is the rate parameter of the exponential, things will not be too bad.
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