Select random elements from three consecutive columns in a big matrix?

Hello all,
I have a 12 by 12 matrix, and I want to select 10 random elements. The elements should be from only three consecutive columns.
For example, I want to use 10 random elements from columns (1, 2, 3) or they could be from columns (2, 3, 4) or columns(3, 4, 5) and so on.
Any help please.
Thanks

댓글 수: 3

10 from each of the columns? 10 total from those 3 columns, with no effort to balance how many are to be taken from each individual column?
Guillaume
Guillaume 2019년 4월 5일
편집: Guillaume 2019년 4월 5일
Please do not ask the same question twice.
And it looks like you delete your question once answered, which is not going to go down well with us (and will be restored anyway).
I am really sorry, it was a mistake. I realized that the question was submitted twice, I tried to delete it as soon as it was submitted but I could not. I apologies for any inconvenience.

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답변 (2개)

N = 10;
[r, c] = size(YourMatrix);
start_col = randi([1, c-2]);
chosen = YourMatrix(start_col * r - 1 + randi([1 3*r], 1, N));
Jos (10584)
Jos (10584) 2019년 4월 5일
편집: Jos (10584) 2019년 4월 5일
M = magic(5) % input data
N = 4 % number of selections
nC = 3 % number of consecutive columns
% engine
szM = size(M)
r = randi(szM(1), N, nC) % N x 3 random rows
c = randi(szM(2) - nC + 1, N, 1) % N random first columns
c = c + [0:nC-1] % add consecutive columns
R = M(sub2ind(szM, r, c)) % index into M

카테고리

도움말 센터File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

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2019년 4월 4일

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2019년 4월 5일

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