If I have x=[0.2 1 0.485 0.13 0.11] , I have Tb=10ms and the fs=16*fb; %Sampling frequency
Ts=1/fs; I would like to integrate the x over Tb. How can I do it without using the integration functions. Using the summing algorithm.

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Walter Roberson
Walter Roberson 2019년 4월 4일
Which "summing algorithm" ?
integrationBase = 0:1/fs:Tb-1/fs;
for i = 0:(length(v)/(Tb*fs))-1,
y1(i+1)=trapz(integrationBase,v(int32(i*Tb*fs+1):int32((i+1)*Tb*fs)));
end
The summing algoithm I mean "summation of the discrate values on the array v"
Walter Roberson
Walter Roberson 2019년 4월 5일
So you are doing trapz() of the v array at the moment, but you feel it would be more accurate to do plain summation? If so why not just reshape v to have Tb*fs rows and sum along the first dimension ?
What reason do you have to expect plain summation to better represent the area than trapz ?

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답변 (1개)

madhan ravi
madhan ravi 2019년 4월 3일

0 개 추천

Perhaps you want to use cumtrapz() or trapz().

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Willim
Willim 2019년 4월 4일
I have using it but It give me a wrong answer , and I believe the summing formula is going to be easirer.

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