How to convert an array of bytes to IEEE 754 single-precision float?

조회 수: 28 (최근 30일)
Minh Tran
Minh Tran 2019년 4월 1일
댓글: Minh Tran 2019년 4월 1일
I'm using Matlab R2007b.
I have an array
[65 227 216 168]
which represents the hexadecimal digits
0x41E3D8A8
that I'd like to interpret as a single-precision IEEE 754 float. The value that float takes on should be approximately 28.4808.
I'm able to use several online calculators to convert 0x41E3D8A8 to ~28.4808 but I can't seem to get that value in Matlab, starting from the array representation of that Hex value. I tried:
single(typecast(uint8([65 227 216 168]), 'uint32')) % Returns 2.8328e+009

채택된 답변

James Tursa
James Tursa 2019년 4월 1일
Try this:
>> swapbytes(typecast(uint8([65 227 216 168]),'single'))
ans =
single
28.4808

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Numeric Types에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by