convert number to string problem

조회 수: 3 (최근 30일)
Yu Li
Yu Li 2019년 3월 10일
댓글: Yu Li 2019년 3월 10일
I have a column number, and I want to add some string in front of it, and assign it to items of a drop-down list in an App.
take the test value test=1:1:5 for example, below is my code:
test=1:1:5;
for i=1:1:length(test)
tmp_name{i}=strcat('Data Set',num2str(test(i)));
end
to improve this code without the for-loop, I found that there is a function 'num2cell' but it does not work in this case:
test=1:1:5;
strcat('CVG Set',num2cell(test))
below is the result:
Capture.JPG
the numbers are converted to a rectangle symbol instead of string.
is there any mistake with my operation?
Bests,
Yu

채택된 답변

madhan ravi
madhan ravi 2019년 3월 10일
sprintfc('Data Set %d',test) % beware undocumented
  댓글 수: 2
madhan ravi
madhan ravi 2019년 3월 10일
Alternative:
cellstr("Data set "+test)
Yu Li
Yu Li 2019년 3월 10일
Thank you.
Bests,
Yu

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추가 답변 (2개)

Geoff Hayes
Geoff Hayes 2019년 3월 10일
Yu - I think the problem might be because when you use num2cell, you are creating a cell array of numbers and not a cell array of strings.
An alternative to what you have written is to use arrayfun where we apply a function to each of our integers (in test). For example,
tmp_name = arrayfun(@(x)sprintf('CVG Set %d',x),1:5, 'UniformOutput', false);
initializes the variable to
tmp_name =
'CVG Set 1' 'CVG Set 2' 'CVG Set 3' 'CVG Set 4' 'CVG Set 5'
which may be sufficient for what you need. You can modify the string in the sprintf call to get a different format (if that is what you need).

Image Analyst
Image Analyst 2019년 3월 10일
Yu:
Try this:
test = 1 : 5;
for k = 1 : length(test)
popupStrings{k} = sprintf('Data Set %d', test(k));
end
celldisp(popupStrings)
% Now load the strings into the popup (drop down list)
handles.popup1.String = popupStrings;
  댓글 수: 2
madhan ravi
madhan ravi 2019년 3월 10일
OP tries to avoid a for-loop.
Yu Li
Yu Li 2019년 3월 10일
Thank you.
Bests,
Yu

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