How to create stacked histogram with arrays of different length

조회 수: 13 (최근 30일)
Gian Violi
Gian Violi 2019년 3월 6일
편집: ch_tsai 2023년 10월 17일
Basically I have column arrays with multiple observations, each belonging to a different category but every element has a different lenght. I want to be able to do something like this, whit each color representing a array (or category).4aBSy.png
I tried to concatenate the arrays into a bigger array and then stacking bars but didn't help beacuse of the lenght issue.
  댓글 수: 2
Martin Roth
Martin Roth 2021년 10월 1일
편집: Martin Roth 2021년 10월 1일
Better late than never. Check if this solution fits for your problem:
% Create dummy data
A=-20+40*rand(500,1);
B=randn(400,1)*20;
Total=[A;B];
Steps=[0,numel(A),numel(B)];
[N,edges,bins] = histcounts(Total);
% Plot stacked histogram
figure;
colors=lines;
hold on
for i=1:length(Steps)-1
histogram(Total(1+Steps(i):end),'BinEdges',edges,'FaceColor',colors(i,:));
hold on
end
ch_tsai
ch_tsai 2023년 10월 17일
편집: ch_tsai 2023년 10월 17일
I was trying to find a similar function and found this answer. Your code looks good, thank you! I would like to make it more generalized. For example, if there are more than two set of data, in the last part of your for loop, it's better to write in this way.
% Copy from your code--
% Create dummy data
A=-20+40*rand(500,1);
B=randn(400,1)*20;
C=-25+40*rand(500,1);
D=randn(400,1)*10;
Total=[A;B;C;D];
Steps=[0,numel(A),numel(B),numel(C),numel(D)];
[N,edges,bins] = histcounts(Total);
% Plot stacked histogram
figure;
colors=lines;
hold on
for i=1:length(Steps)-1
histogram(Total(1+sum(Steps(1:i)):end),'BinEdges',edges,'FaceColor',colors(i,:));%sum of Steps(1:i) was added
hold on
end

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