Creating possible addition of a number

조회 수: 1 (최근 30일)
fyza affandi
fyza affandi 2019년 2월 24일
댓글: fyza affandi 2019년 2월 24일
I have a set of array A
A= [1 2 4 8 16]
For example I want a set of number that make up total of 4 (from A), it would be
B=[1 1 1 1] *total in array B would be 4*
B=[1 1 2]
B=[2 2]
B=[4]
Is it possible to do it in Matlab?
  댓글 수: 1
Rik
Rik 2019년 2월 24일
It is possible to this in Matlab. How would you try to solve it?

댓글을 달려면 로그인하십시오.

채택된 답변

John D'Errico
John D'Errico 2019년 2월 24일
편집: John D'Errico 2019년 2월 24일
Trivial, if you download my partitions function from the File Exchange.
A = [1 2 4 8 16];
partitions(4,A)
ans =
4 0 0 0 0
2 1 0 0 0
0 2 0 0 0
0 0 1 0 0
Each row of the result tells you how many times that element appears in the target sum.
Find it here:
Note that the number of such partitions can be immense for some problems. You can easily overwhelm such a tool. For example, I have another utiility that will count the number of partitions of an integer.
numberOfPartitions(1000)
ans =
24061467864032622473692149727991
Thus as the sum of numbers in the set [1:1000]. It gets big, and does so pretty fast.

추가 답변 (1개)

Stephen23
Stephen23 2019년 2월 24일
Download John D'Errico's excellent partitions:
and use it like this:
>> A = [1,2,4,8,16];
>> M = partitions(4,A);
>> F = @(v)repelem(A,v);
>> C = cellfun(F,num2cell(M,2),'uni',0);
>> C{:}
ans =
1 1 1 1
ans =
1 1 2
ans =
2 2
ans =
4
  댓글 수: 2
John D'Errico
John D'Errico 2019년 2월 24일
One of the things I should have added as an option, was the ability to return the partitions in an expanded form, something much like Stephen did here. You can never have too many options in an interface. Well, at least not until you do. ;-)
fyza affandi
fyza affandi 2019년 2월 24일
Thank you very much :)

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Multidimensional Arrays에 대해 자세히 알아보기

태그

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by