Removing elements of array by condition and without resizing?

I'm trying to produce an array to later write into a .txt file. Currently, the array I am working with is a 5323x18 double. Due to the nature of its conception, roughly all the first 3-5 columns contain a non-zero numerical value, while the other columns (6-18) occasionally contains a non-zero numerical value. The rest of the elements of the array are zero. In order to ensure that the .txt file doesn't have any of these zeros, is there any way I can delete those elements from the array, while maintaining the array size?
For example, turning something like the following array:
[ 1 5 0 0 0 0
1 5 6 7 0 0
4 0 0 0 0 0
5 5 5 5 5 5]
to
[ 1 5
1 5 6 7
4
5 5 5 5 5 5]

답변 (1개)

madhan ravi
madhan ravi 2019년 2월 19일
Result=arrayfun(@(x)nonzeros(a(x,:)).',1:size(a,1),'un',0); % where a is your matrix
celldisp(Result)

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Is there a way to also separate the values in square brackets in the result cell that is formed?
matrix cannot have holes so cell array is preferred
And is it possible for the cell array to have holes?
yes by holes I mean empty
Ah, I see. I was hoping that the resultant combined row data in square brackets could be separated into their own cells.

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도움말 센터File Exchange에서 Resizing and Reshaping Matrices에 대해 자세히 알아보기

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2019년 2월 19일

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2019년 2월 19일

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