Hello,
If you see the picture below, I am representing dinamically the blue point with a matrix and imagesc function. What I would like to do is filling the gap bewteen points with more points, so the final graph woould look like a line.
Untitled.jpg
An example how I am plotting the graph
% First point position in the matrix
0 0 0 1 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0
% Next time period the matrix will have other values for the second "blue" point
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 0 0
0 0 0 0 0 1 0
% I would like to get automatically a matrix that interpolate between both "1" values and get something like below to draw a line,
0 0 0 1 0 0 0
0 0 0 0 1 0 0
0 0 0 0 1 0 0
0 0 0 0 0 1 0
I hope to make myself clear,
Thanks in advance!

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Akira Agata
Akira Agata 2019년 2월 18일

0 개 추천

How about the following?
% First point position in the matrix
M1 = [0 0 0 1 0 0 0;
0 0 0 0 0 0 0;
0 0 0 0 0 0 0;
0 0 0 0 0 0 0];
% Next time period the matrix will have other values for the second "blue" point
M2 = [0 0 0 0 0 0 0;
0 0 0 0 0 0 0;
0 0 0 0 0 0 0;
0 0 0 0 0 1 0];
[row,col] = find(M1 | M2);
row2 = (1:4)';
col2 = round(interp1(row,col,row2));
M3 = zeros(size(M1));
M3(sub2ind(size(M3),row2,col2)) = 1;
The result is:
>> M3
M3 =
0 0 0 1 0 0 0
0 0 0 0 1 0 0
0 0 0 0 1 0 0
0 0 0 0 0 1 0

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Jose Martinez
Jose Martinez 2019년 2월 19일
Brilliant, I think the idea will work wit my project!
Thank you so much

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도움말 센터File Exchange에서 Creating and Concatenating Matrices에 대해 자세히 알아보기

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