Waterfall plot of an integral

조회 수: 2 (최근 30일)
Andrew Heinrich
Andrew Heinrich 2019년 2월 11일
답변: Raghav Singhal 2019년 2월 27일
I am attempting to create a waterfall plot of an integrated function where one of the bounds is a variable. I am very new to matlab so I am not sure if the answer is glaringly obvious, but trying different things gets me different errors, either with horzcat or with non-numeric inputs for the waterfall command. Any advice is appreciated.
x = linspace(-3,3,20);
y = linspace(.01,1,20);
T= linspace(0,1,20);
[X,Y]= meshgrid(x,y);
f = (4.*pi.*(Y-T)).^-1/2.*exp(-X.^2./(4.*(Y-T)));
syms T Y
Z= int(f,T,[0 Y]);
figure
waterfall(X,Y,Z)

답변 (1개)

Raghav Singhal
Raghav Singhal 2019년 2월 27일
Hi, the expression 'f' you have defined is of type double, ie it has no variables and hence integrating such an expression wouldnt work. You could try defining the variables used as symbolic beforehand and try. Additionally since you seem to be integrating an expression with three variables, you could try using 'integral3' instead of 'int'.
Doucumentation for the same can be found here. Hope this helps.

카테고리

Help CenterFile Exchange에서 Calculus에 대해 자세히 알아보기

제품


릴리스

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by